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b^2=36/169
We move all terms to the left:
b^2-(36/169)=0
We add all the numbers together, and all the variables
b^2-(+36/169)=0
We get rid of parentheses
b^2-36/169=0
We multiply all the terms by the denominator
b^2*169-36=0
Wy multiply elements
169b^2-36=0
a = 169; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·169·(-36)
Δ = 24336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{24336}=156$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-156}{2*169}=\frac{-156}{338} =-6/13 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+156}{2*169}=\frac{156}{338} =6/13 $
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